The excitement level is so up that i couldn’t stop myself from writing this post.

Well , may not be a very big deal for everyone but it sure is a big thing to me. Yes , right now i feel like i am on cloud 9 ðŸ™‚

Few days back , in one of our labs , we were supposed to write a C program and the question given was quite complicated for one to first understand.. It took me almost two hours,Â sitting and thinking on what should i do..

I knew every logic that the question had.. but i had to struggle enough to write the code.

I will mention the question along with an example so that it is clear ðŸ™‚

The question “just” said to round an “integer” not any specific but can be rounded upto any roundup digit ( which means , we take the roundup digit ). Simple isn’t it ? ðŸ˜€

Well , it should include all the rounding off rules :

1. If it is to be rounded till m places , we note the ‘n’th’ digit , and check the ‘n+1’th’ digit

a. if the n+1’th digit is greater than 5, the n’th digit increases by 1

b. if the n+1’th digit is less than 5, the n’th digit remains the same.

2. IfÂ it is to be rounded till m place, we note the note ‘n’th’ digit AND if the ‘n+1’th’ digit is 5

a. then the n’th digit , if even, then remains the same.

b. then the n’th digit , if odd , increase the n’th digit by 1.

Example –

1 . if the number is – 23476 : should be rounded to m= 4 places : so, n= 7 and n+1= 6

then the output should be – 2348

2. if the number is – 23474 : should be rounded to m= 4 places : so, n= 7 and n+1= 4

then the output should be – 2347

3. if the number is – 23465 : should be rounded to m = 4 places : so, n= 7 and n+1= 5

then the output should be – 2346

4. if the number is – 23475 : should be rounded to m = 4 places : so, n= 6 and n+1= 5

then the output should be – 2348

Lots of logic. Unluckily, none of the students could do it ðŸ˜¦ including me ðŸ˜› many students tried google , but even google failed to answer them.

I felt bad, not because i couldn’t write the code in the class but because inspite of knowing the entire logic i couldn’t frame the code.

The day ended, i came back to the room and just bumped on the bed.. Stretched my legs , glued my eyes to the screen , took a pen and paper and started writing whatever i had in mind. My code was a little messy , it gave errors at few points. Finally , i asked for help from sayan da , and may be i couldn’t properly explain the question to him.

The only thing that i missed doing was:

y=num;

while(y!=0)

{

nobit++;

y=y/10;

}

and the rest everything was perfect. I was okay with the my code ðŸ™‚ thanks to kartick for making me help with this little thing.

Here is the code:

#include<stdio.h>

main()

{

int num, abc, bit, bit1, i, y, nobit=0, div=1, round;

printf(“please enter a number: “);

scanf(“%d”, &num);//enter number

y=num;

while(y!=0)

{

nobit++;

y=y/10;

}

printf(“Please enter the the roundup digit: “);

scanf(“%d”, &round);//enter rounding digit

for(i=nobit; i>ask;i–)

div*=10;

abc=num/div;

bit=abc%10;

bit1=(num/(div/10))%10

/*Â Â Â Â Â printf(“%d\n”,abc);

printf(“%d\n”,bit);

printf(“%d\n”, bit1);*/

if(bit1<5)

printf(“%d”, abc);

if(bit1>5)

printf(“%d”, abc+1);

if(bit1==5)ell

{

if(bit%2==1)

printf(“%d”,abc+1);

else

printf(“%d”,abc);

}

}

Felt really good after seeing my entire logic working right in front of my eyes.

This went a little long but was worth writing ðŸ™‚

P.S – Dry run really helps ðŸ™‚